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For questions 1-3, use the following information:

B = allele for short fingers (dominant)

b = allele for normal fingers (recessive)

G = allele for the ability to blow large bubbles from bubble gum (dominant)

g = allele for the lack of ability to blow large bubbles from bubble gum (recessive)

(The alleles G/g are not real; they are just there for the exerciseJ )

Question 1:

What are all the possible genotypes of the offspring of the cross:  Bb x Bb

 All possible offspring are (0.5 pts):

  a) BB and bb

  b) BB and Bb

  c) B and b

  d) BB, Bb and bb

Question 2:

A woman, homozygous for short fingers, marries a man with normal fingers. What are all the possible genotypes and the corresponding phenotypes of the offspring (0.5 pts)?

All possible genotypes are:

  a) BB, Bb and bb

  b) BB and bb

  c) all Bb

  d) BB, and Bb

All possible phenotypes are: (0.5pts)

  a) short and normal

  b) short

  c) normal

Question 3:

Determine all possible genotypes of the offspring of these parents (0.5 pts):

Mother: doubly homozygous for short fingers and ability to blow large bubbles

Father:  normal fingers with no ability to blow large bubbles

All possible offspring are:

  a) BG and bg

  b) BBGG, BbGg, bbGg and bbgg

  c) all BbGg

  d) BB, GG, bb and gg

For questions 4-6, use the following mating:

S= Sticky yellow earwax (dominant)

s = grey earwax

C= does not have cystic fibrosis (dominant)

c = have cystic fibrosis (recessive). 

(The alleles S/s are real alleles, believe it or not!)

Question 4:

A mother and father are both heterozygous for these 2 traits mentioned above. 

What would be the possible combinations of alleles the mother or the father could produce in their gametes?

(0.5pts)

a.  SC only

b.  sc and SC only

c.  sc only

d.  SC, sc, and Sc only

e.  SC, sc, Sc, and sC only

Question 5: 

Every time the parents reproduce, what is the expected genotypic ratio? (0.5 pts)

a.  1 SSCC: 2 SSCc: 2 SsCC: 4 SsCc: 1 SScc: 2 Sscc: 1 ssCC: 2 ssCc: 1 sscc

b.  1 SSCC: 4 SSCc: 4 SsCc: 1 SScc: 2 Sscc: 1 ssCC: 2 ssCc: 1 sscc

c.  2 SSCc: 2 SsCC: 6 SsCc: 1 SScc: 2 Sscc: 1 ssCC: 2 ssCc

d.  2 SSCC: 1 SSCc: 2 SsCC: 4 SsCc: 1 SScc: 2 Sscc: 1 ssCC: 1 ssCc: 2 sscc

e.  Cannot know from the information given.

Question 6:  (0.5 pts)

If they have several children, is it possible that all the children will have sticky yellow earwax and cystic fibrosis?  Why?

a.  No, at least one child will get the dominant allele for no cystic fibrosis.

b.  No, all the children will get the dominant allele for no cystic fibrosis.

c.  Yes, all the children must get the allele for sticky yellow earwax because it is dominant.

d.  Yes, it is possible because all the combinations are possible; however, it is not likely.

e.  Cannot tell from the information given.

Question 7:

In a given population, the following number of people is observed with the given

MN blood types:

Blood types:            MM                          MN                          NN

Numbers:                480                          60                            60

 What are the genotype frequencies? (1pt)

Question 8: (1 pt)

What are the allele frequencies of that population?

Question 9:

In the next generation we observe the following number of people with the given blood types:

Blood types:            MM                          MN                          NN

Numbers:                91                            300                          9

What are the genotype frequencies? (1pt)

What are the allele frequencies? (1pt)

Are the allele frequencies the same as in the first generation? (1pt)

What can you say about the population? Explain. (1pt)

Question 10:

In a population we have S for sticky yellow earwax allele and s for grey earwax allele.  The genotype frequencies are SS = 0.2; Ss = 0.8 and ss = 0.0.  Calculate the allele frequencies. (0.5)

 


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