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When a particle moves at high velocity, its mass m is different from its mass m0 at rest according to the following formula: m= (m0/ sqrt(1 - (v^2/c^2))) where v= v(t) is the velocity at time t and c= 2.98 x 10^8 m/sec is the speed of light.

a) Verify that if v=0 then m= m0. What happens if v -> c? b) Knowing Â that the acceleration is the derivative dv/dt of the velocity, write the related rates formula for dm/dt in terms of dv/dt. c) Compute the rate at which the mass m(t) is changing when the velocity is 2.60x10^5 m/sec^2.

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