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(Solved) Sample Item 1 1 2 3 4 5 6.85 6 6.15 item 2 item 3 Item 4 Item 5 6.01 Xbar R 5.906 6.074 6.942 6 5.9904 Average R Chart D3 D4 UCL = X-double bar +A2*...


3)     For the data in Problem 2, if the true mean and standard deviation of the process are 6.05 and 0.04. 

a.      Is this process capable of meeting its specification? Calculate its Cp and CPk.

b.     What % of cylinders are out of specs?


Please reference question 2 tab which i have already answered. just need help for the above question. Would like it answered today

Sample Item 1
1
2
3
4
5 6.1
6.35
5.85
6
6.15 item 2
item 3
Item 4
Item 5
6.15
5.35
5.98
5.95
6.02
6.2
6.1
5.7
5.9
6.2
6.12
6.08
5.8
5.7
6.04
6.17
5.6
6.25
5.99
6.01 Xbar R
5.906
6.074
6.03
5.942
6
5.9904 Average R Chart
D3
D4 UCL = X-double bar +A2* Rbar =
LCL =X doublebar - A2 * R bar =
A2
n= 0.8
0.65
0.35
0.47
0.65
0.584 0.5777
5 R Chart
6.4
1.4 6.2 1.2 6 1
0.8 5.8 0.6 5.6 0.4
5.4 0.2
0 1 2
Column I 3
Column M 4
Column N 5
Column O 5.2 1 2
Column H Xbar
LCL
CL
5.653023
5.653023
5.653023
5.653023
5.653023 5.9904
5.9904
5.9904
5.9904
5.9904 UCL
6.327777
6.327777
6.327777
6.327777
6.327777 R Chart
LCL CL
0
0
0
0
0 0.584
0.584
0.584
0.584
0.584 UCL
1.234576
1.234576
1.234576
1.234576
1.234576 0
2.114 X Bar Chart
6.4
6.2
6
5.8
5.6
5.4
5.2 1 2
Column H 3
Column J 4
Column K 5
Column L Frequency
(number of times)
Items damaged when received
21
Parts missing
13
Literature not in the box
9
Call went to voice mail
8
Delivery was late
3
Unit not working
2
Type of Problem Cummlative Cummalative%
21
38%
34
61%
43
77%
51
91%
54
96%
56
100% 56 Chart Title
25
20
15
10
5
0 120%
100%
80%
60%
40%
20%
0% Frequency (number of times) Cummalative% 120%
100%
80%
60%
40%
20%
0%

 


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